//题目：给一个不多于5位的正整数，要求：一、求它是几位数，二、逆序打印出各位数字。
//1. 程序分析：学会分解出每一位数，如下解释：(这里是一种简单的算法，师专数002班赵鑫提供)
//2.程序源代码：
#include "stdio.h"
int main() {
	long a, b, c, d, e, x;
	scanf("%ld", &x);
	a = x / 10000;/*分解出万位*/
	b = x % 10000 / 1000;/*分解出千位*/
	c = x % 1000 / 100;/*分解出百位*/
	d = x % 100 / 10;/*分解出十位*/
	e = x % 10;/*分解出个位*/
	if (a != 0)
		printf("there are 5, %ld %ld %ld %ld %ld\n", e, d, c, b, a);
	else if (b != 0)
		printf("there are 4, %ld %ld %ld %ld\n", e, d, c, b);
	else if (c != 0)
		printf(" there are 3,%ld %ld %ld\n", e, d, c);
	else if (d != 0)
		printf("there are 2, %ld %ld\n", e, d);
	else if (e != 0)
		printf(" there are 1,%ld\n", e);
}
